x86: Avoid double stack traces with show_regs()

What was called show_registers() so far already showed a stack
trace for kernel faults, and kernel_stack_pointer() isn't even
valid to be used for faults from user mode, hence it was
pointless for show_regs() to call show_trace() after
show_registers().

Simply rename show_registers() to show_regs() and eliminate
the old definition.

Signed-off-by: Jan Beulich <jbeulich@suse.com>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Andrew Morton <akpm@linux-foundation.org>
Cc: Arjan van de Ven <arjan@linux.intel.com>
Cc: Frederic Weisbecker <fweisbec@gmail.com>
Link: http://lkml.kernel.org/r/4FAA3D3902000078000826E1@nat28.tlf.novell.com
Signed-off-by: Ingo Molnar <mingo@kernel.org>
This commit is contained in:
Jan Beulich 2012-05-09 08:47:37 +01:00 committed by Ingo Molnar
parent febb72a6e4
commit 57da8b960b
7 changed files with 6 additions and 13 deletions

View file

@ -24,7 +24,6 @@ enum die_val {
extern void printk_address(unsigned long address, int reliable);
extern void die(const char *, struct pt_regs *,long);
extern int __must_check __die(const char *, struct pt_regs *, long);
extern void show_registers(struct pt_regs *regs);
extern void show_trace(struct task_struct *t, struct pt_regs *regs,
unsigned long *sp, unsigned long bp);
extern void __show_regs(struct pt_regs *regs, int all);