modpost: strip .o from modname before calling new_module()

new_module() conditionally strips the .o because the modname has .o
suffix when it is called from read_symbols(), but no .o when it is
called from read_dump().

It is clearer to strip .o in read_symbols().

I also used flexible-array for mod->name.

Signed-off-by: Masahiro Yamada <masahiroy@kernel.org>
This commit is contained in:
Masahiro Yamada 2020-06-01 14:57:29 +09:00
parent 858b937d28
commit a82f794c41
2 changed files with 12 additions and 10 deletions

View file

@ -175,18 +175,12 @@ static struct module *find_module(const char *modname)
static struct module *new_module(const char *modname)
{
struct module *mod;
char *p;
mod = NOFAIL(malloc(sizeof(*mod)));
mod = NOFAIL(malloc(sizeof(*mod) + strlen(modname) + 1));
memset(mod, 0, sizeof(*mod));
p = NOFAIL(strdup(modname));
/* strip trailing .o */
if (strends(p, ".o"))
p[strlen(p) - 2] = '\0';
/* add to list */
mod->name = p;
strcpy(mod->name, modname);
mod->is_vmlinux = is_vmlinux(modname);
mod->gpl_compatible = -1;
mod->next = modules;
@ -2013,7 +2007,15 @@ static void read_symbols(const char *modname)
if (!parse_elf(&info, modname))
return;
mod = new_module(modname);
{
char *tmp;
/* strip trailing .o */
tmp = NOFAIL(strdup(modname));
tmp[strlen(tmp) - 2] = '\0';
mod = new_module(tmp);
free(tmp);
}
if (!mod->is_vmlinux) {
license = get_modinfo(&info, "license");