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sched: Remove SYNC_WAKEUPS feature
Sync wakeups are critical functionality with a long history. Remove it, we don't need the branch or icache footprint. Signed-off-by: Mike Galbraith <efault@gmx.de> Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl> LKML-Reference: <1268301817.6785.47.camel@marge.simson.net> Signed-off-by: Ingo Molnar <mingo@elte.hu>
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2 changed files with 0 additions and 11 deletions
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@ -2369,9 +2369,6 @@ static int try_to_wake_up(struct task_struct *p, unsigned int state,
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unsigned long flags;
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unsigned long flags;
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struct rq *rq;
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struct rq *rq;
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if (!sched_feat(SYNC_WAKEUPS))
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wake_flags &= ~WF_SYNC;
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this_cpu = get_cpu();
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this_cpu = get_cpu();
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smp_wmb();
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smp_wmb();
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@ -22,14 +22,6 @@ SCHED_FEAT(WAKEUP_PREEMPT, 1)
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*/
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*/
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SCHED_FEAT(ASYM_GRAN, 1)
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SCHED_FEAT(ASYM_GRAN, 1)
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/*
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* Use the SYNC wakeup hint, pipes and the likes use this to indicate
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* the remote end is likely to consume the data we just wrote, and
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* therefore has cache benefit from being placed on the same cpu, see
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* also AFFINE_WAKEUPS.
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*/
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SCHED_FEAT(SYNC_WAKEUPS, 1)
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/*
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/*
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* Based on load and program behaviour, see if it makes sense to place
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* Based on load and program behaviour, see if it makes sense to place
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* a newly woken task on the same cpu as the task that woke it --
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* a newly woken task on the same cpu as the task that woke it --
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