debugfs: remove return value of debugfs_create_x8()

No one checks the return value of debugfs_create_x8(), as it's not
needed, so make the return value void, so that no one tries to do so in
the future.

Link: https://lore.kernel.org/r/20191011132931.1186197-5-gregkh@linuxfoundation.org
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
This commit is contained in:
Greg Kroah-Hartman 2019-10-11 15:29:28 +02:00
parent ff229319f4
commit c7c1168909
3 changed files with 9 additions and 13 deletions

View file

@ -633,10 +633,10 @@ DEFINE_DEBUGFS_ATTRIBUTE(fops_x64_wo, NULL, debugfs_u64_set, "0x%016llx\n");
* @value: a pointer to the variable that the file should read to and write
* from.
*/
struct dentry *debugfs_create_x8(const char *name, umode_t mode,
struct dentry *parent, u8 *value)
void debugfs_create_x8(const char *name, umode_t mode, struct dentry *parent,
u8 *value)
{
return debugfs_create_mode_unsafe(name, mode, parent, value, &fops_x8,
debugfs_create_mode_unsafe(name, mode, parent, value, &fops_x8,
&fops_x8_ro, &fops_x8_wo);
}
EXPORT_SYMBOL_GPL(debugfs_create_x8);