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tracing: Still trace filtered irq functions when irq trace is disabled

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If a function is set to be traced by the set_graph_function, but the
option funcgraph-irqs is zero, and the traced function happens to be
called from a interrupt, it will not be traced.

The point of funcgraph-irqs is to not trace interrupts when we are
preempted by an irq, not to not trace functions we want to trace that
happen to be *in* a irq.

Luckily the current->trace_recursion element is perfect to add a flag
to help us be able to trace functions within an interrupt even when
we are not tracing interrupts that preempt the trace.

Reported-by: Heiko Carstens <heiko.carstens@de.ibm.com>
Tested-by: Heiko Carstens <heiko.carstens@de.ibm.com>
Signed-off-by: Steven Rostedt <rostedt@goodmis.org>
This commit is contained in:
Steven Rostedt 2011-06-14 19:02:29 -04:00 • committed by Steven Rostedt
parent e08fbb78f0
commit e4a3f541f0
2 changed files with 35 additions and 17 deletions
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2
kernel/trace/trace_functions_graph.c
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@ -227,7 +227,7 @@ int __trace_graph_entry(struct trace_array *tr,
static inline int ftrace_graph_ignore_irqs(void)
{
if (!ftrace_graph_skip_irqs)
if (!ftrace_graph_skip_irqs || trace_recursion_test(TRACE_IRQ_BIT))
return 0;
return in_irq();